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Cobalt forms two common ion oxidation states, Co+3 and Co+3. When solid cobalt is reacted with a gold (III) chloride solution, two reactions are possible, as shown in the following equations:

Reaction 1) AuCl3 (aq) + Co(s) → Au(s) + CoCl3 (aq)

Au+3(aq) + Co(s) → Au(s) + Co+3(aq)

Reaction 2) 2 AuCl3 (aq) + 3 Co(s) → 2 Au(s) + 3 CoCl2 (aq)

2 Au+3(aq) + 3 Co(s) → 2 Au(s) + 3 Co+2(aq)

If reaction 1 is correct how many grams of solid gold (MW = 196.967) will be produced if 10.000 grams of cobalt metal (MW=58.933) is reacted with an excess of gold (III) chloride? (record your answer to 3 decimal places and do not add a unit ie g)

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dsdrajlin

10.000 g of cobalt react with an excess of gold (III) chloride to form 33.422 g of gold and cobalt (III) chloride.

What is stoichiometry?

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

Let's consider the balanced equation that occurs when solid cobalt reacts with gold (III) chloride.

AuCl₃ (aq) + Co(s) → Au(s) + CoCl₃ (aq)

We want to calculate the mass of Au produced from the reaction of 10.000 g of Co.

We will consider the following relationships.

  • The molar mass of Co is 58.933 g/mol.
  • The molar ratio of Co to Au is 1:1.
  • The molar mass of Au is 196.967 g/mol.

[tex]10.000 g Co \times \frac{1molCo}{58.933gCo} \times \frac{1molAu}{1molCo} \times \frac{196.967gAu}{1molAu} = 33.422gAu[/tex]

10.000 g of cobalt react with an excess of gold (III) chloride to form 33.422 g of gold and cobalt (III) chloride.

Learn more about stoichiometry here: https://brainly.com/question/16060223

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