Answer:
[tex]\frac{3}{10}[/tex]
Step-by-step explanation:
The average rate of change of a function over the interval [tex][a,b][/tex] is [tex]\frac{f(b)-f(a)}{b-a}[/tex].
Since [tex][a,b]\rightarrow[0,20][/tex], then for throw #3:
[tex]\frac{f(b)-f(a)}{b-a}\\\\\frac{f(20)-f(0)}{20-0}\\\\\frac{12-6}{20}\\ \\\frac{6}{20}\\ \\\frac{3}{10}[/tex]
This means that the average rate of change over the interval [0,20] for Throw #3 is [tex]\frac{3}{10}[/tex].
