lajuanukun47 lajuanukun47

11-03-2022
Mathematics

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The nth term of a sequence is 4n^2 -n-1. What is the 11th term of the sequences?

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Angie432 Angie432

11-03-2022

Answer:

The 11th term is 472

Step-by-step explanation:

[tex] t_{n} = 4 {n}^{2} - n - 1[/tex]

[tex] t_{11} = 4 \times {11}^{2} - 11 - 1[/tex]

[tex] = 4 \times 121 - 12 \\ = 484 - 12 \\ = 472[/tex]

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