Answer:
[tex]2-\sqrt{3}[/tex]
Step-by-step explanation:
[tex]tan15 = tan(45 - 30)=\frac{\tan{45}-\tan{30}}{1+\tan{45}\tan{30}}\\\\=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}\\\\\\=\frac{\sqrt{3}-1}{\sqrt{3}+1}\\\\\\[/tex]
[tex]=\frac{(\sqrt{3}-1)^2}{3-1}\\=\frac{3+1-2\sqrt{3}}{2}\\=2-\sqrt{3}[/tex]
