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  • 15-03-2022
  • Mathematics
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An alloy contains 26 % of copper. What quantity of alloy is required to get 260 g of copper?​

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Аноним Аноним
  • 15-03-2022

Solution:

Let the quantity of alloy required = m g

Then 26 % of m =260 g

[tex]\small\bold\green{⇒}\small\bold{\frac{(26)}{100} × m = 260 g}[/tex]

[tex]\small\bold\green{⇒}\small\bold{m = \frac{(260 × 100)}{26} g}[/tex]

[tex]\small\bold\green{⇒}\small\bold{m = \frac{26000}{26} g}[/tex]

[tex]\small\bold\green{⇒}\small\bold{m = 1000 g}[/tex]

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