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12-04-2022
Mathematics

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For what value(s) of b will cause 6x^2+bx-7=0 to have two real number solutions

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Аноним Аноним

12-04-2022

Answer:

B can be All real values.

Step-by-step explanation:

The discriminant = b^2 - 4*6*-7 > 0

b^2 + 168 > 0

b^2 > -168

All values of b will be > 0.

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