Respuesta :

Answer:

[tex]ph \: of \: a \: solution \: = - \: log \: ( {h}^{ + } ) \\ given \: ( {h}^{ + } ) = 2 \times {10}^{ - 5} \\ = ph = - log \: (2 \times {10}^{ - 5} ) \: = 5 - log \: 2 = 4.7[/tex]