[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &9152\\ t=\textit{elapsed time}\dotfill &12\\ h=\textit{half-life}\dotfill &3 \end{cases} \\\\\\ A=9152\left( \frac{1}{2} \right)^{\frac{12}{3}}\implies A=9152\left( \frac{1}{2} \right)^4\implies A=572[/tex]
