Respuesta :

plasticpinktrees

Answer:

(3a+3b+1)(2a+2b+3)

Step-by-step explanation:

This is the farthest they could be factored

#1

  • 6(a+b)²+11(a+b)+3

Let a+b=x

  • 6x²+11x+3
  • 6x²+2x+9x+3
  • 2x(3x+1)+3(3x+1)
  • (2x+3)(3x+1)

Put value

  • (2(a+b)+3)(3(a+b)+1)

#2

  • 8(x+1)²-14(x+1)+3

Let x+1=y

  • 8y²-14y+3
  • 8y²-2y-12y+3
  • 2y(4y-1)-3(4y-1)
  • (2y-3)(4y-1)

Put value

  • (2(x+1)-3)(4(x+1)-3)

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