Answer:
hope this will help you (•‿•)
Step-by-step explanation:
[tex]for \: 1st \: qn \: \\ let \: the \: angle \: be \gamma \\ \cos( \beta ) = \frac{b}{p} \\ \cos( \beta ) = \frac{16}{34} \\ \beta = \cos {}^{ - 1} ( { 0.470}^{ } ) \\ \beta = 61.965 \\ for \: 2nd \: qn \\ let \: the \: angle \: be \: \alpha \\ \tan( \alpha ) = \frac{p}{b} \\ \tan( \alpha ) = \frac{20}{15} \\ \alpha = \tan {}^{ - 1} (1.33) \\ \alpha = 53.061[/tex]
