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12-05-2022
Physics

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A 100 kg object moving at 20 m/s comes to a stop over a distance of 40 m. what is the coefficient of kinetic friction between the object and the ground? (show work please)

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jsimpson11000 jsimpson11000

12-05-2022

Answer:

.5097

Explanation:

Original KE = 1/2 (100)(20)^2 = 20 000 J

the force of friction must work this hard to stop the object in 40 m

Ff *40 = 20 000

Ff = 500 = Fn u u = coeff of kinetic friction

500 = (100)(9.81) u

u = .5097

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