farhan3khiro farhan3khiro
  • 11-06-2022
  • Chemistry
contestada

How many moles of zncl2 can be prepared from the reaction of 1.14 grams of zinc with excess HCI? Zn+2HCI=ZnCl2+H2

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Medunno13
Medunno13 Medunno13
  • 13-06-2022

Answer: 0.02 mol

Explanation:

The atomic mass of zinc is 65.409 g/mol, so 1.14 grams of zinc is about [tex]\frac{1.14}{65.409}=0.0174287942[/tex] moles.

From the equation, we know that for every mole of zinc consumed, there is 1 mole of zinc(II) chloride produced, so about 0.02 moles can be prepared.

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