farhan3khiro farhan3khiro
  • 11-06-2022
  • Chemistry
contestada

How many grams of lead(II) nitrate, pb(NO3)2,are present in 4.05 moles

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skytimex2012
skytimex2012 skytimex2012
  • 11-06-2022
1340 is the answer I think
Answer Link
jsimpson11000 jsimpson11000
  • 11-06-2022

Answer:

1341.1737 gm in 4.05 moles

Explanation:

From periodic table

  mole weight pb = 207.2  gm

                         N   14.007      *2 = 28.014 g,

                          O  15.99        *6 = 95.94  gm

total= 331.154 gm per mole     * 4.05 moles =

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