[tex]~~~\dfrac{(-6 +i)}{(1- 2i)}\\\\\\=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{-6-12i+i+2i^2}{1-(2i)^2}\\\\\\=\dfrac{-6-11i-2}{1+4}~~~~~~~~~~~~~;[i^2=-1]\\\\\\=\dfrac{-8-11i}{5}\\\\\\=-\dfrac 85-\dfrac{11}{5}i[/tex]
[tex]\dfrac{-6+i}{1-2i}=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}=\dfrac{-6-12i+i-2}{1+4}=\dfrac{-8-11i}{5}=-\dfrac{8}{5}-\dfrac{11}{5}i[/tex]
