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13-06-2022
Chemistry

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help me please urgently needed

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Respuesta :

13-06-2022

Answer:

(i)

(ii) 10s

Explanation:

u=144km/h=(144× 5/18) m/s=40m/s

v=0

s=200m

By third equation of motion, v ²= u²+ 2as

0=(40)²+ 2a(200)

−1600=400a

a=−4m/s²

Now, by first equation of motion, v=u+at

0=40+(−4)(t)

−40=−4t

t=10sec

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