Answer:
Step-by-step explanation:
area of trapezium ABCD
=(16.5+12)/2 \times 15
=(28.5)/2 \times 15
=213.75 cm^2
[tex]\frac{PQ}{DC} =\frac{8}{12} =\frac{2}{3}[/tex]
Area of PQRS
=213.75 \times (\frac{2}{3} )^2\\=213.75 \times\frac{4}{9} \\=95 ~cm^2
area of green portion=213.75-95=118.75 cm²
