jack0772 jack0772
  • 12-07-2022
  • Mathematics
contestada

For what value of y does 125 =
(1/25)^y-1

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 12-07-2022

Answer:

[tex] y = -\dfrac{1}{2} [/tex]

Step-by-step explanation:

I assume that y - 1 is an exponent, and the equation is

[tex] 125 = (\dfrac{1}{25})^{y - 1} [/tex]

[tex] 5^3 = (5^{-2})^{y - 1} [/tex]

[tex] 5^3 = 5^{-2y + 2} [/tex]

[tex] -2y + 2 = 3 [/tex]

[tex] -2y = 1 [/tex]

[tex] y = -\dfrac{1}{2} [/tex]

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