gay12341 gay12341
  • 14-08-2022
  • Mathematics
contestada

how do you factor 4m^3+12xm^3-8m^2-24m using GCF

Respuesta :

tmarsheuna63
tmarsheuna63 tmarsheuna63
  • 14-08-2022

Answer:

[tex]4m(m {}^{2} + 3xm {}^{2} - 2m - 6)[/tex]

Step-by-step explanation:

[tex]1. \: gcf = 4m \\ 2. \: 4m( \frac{4m {}^{3} }{4m} + \frac{12xm {}^{3} }{4m} + \frac{ - 8m {}^{2} }{4m} + \frac{ - 24m}{4m} ) \\ 3. \: 4m(m {}^{2} + 3xm {}^{2} - 2m - 6)[/tex]

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