Answer:
[tex]f' \left(\dfrac{\pi}{3}\right) =\dfrac{1}{2}[/tex]
Step-by-step explanation:
Given function:
[tex]f(x)=\sin x[/tex]
The differentiation of sin(x) is cos(x).
[tex]\implies f'(x)=\cos x[/tex]
Therefore:
[tex]\implies f' \left(\dfrac{\pi}{3}\right) = \cos \left(\dfrac{\pi}{3}\right)[/tex]
[tex]\implies f' \left(\dfrac{\pi}{3}\right) =\dfrac{1}{2}[/tex]
