Answer:
- Assuming 6 was height and 4 was the side A = 12, P = 17
- A = 48, P = 28
1. (Area, part AA)
[tex]A = \frac{6 \times 4}{2} = 12[/tex]
1. (Perimeter, part AB)
[tex]P = 6 + 4 + 7 = 17[/tex]
2. (Area, part BA)
[tex]A = \frac{4+12}{2} \times 6 = 48[/tex]
2. (Perimeter, part BB)
[tex]P = 4 + 12 + 6 + 6 = 28[/tex]
