ryanspaulding11 ryanspaulding11

14-02-2017
Mathematics

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Find the z-score that has 62.8% of the distribution’s area to its left

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LammettHash LammettHash

14-02-2017

[tex]\mathbb P(Z<z)=F_Z(z)=0.628\implies z={F_Z}^{-1}(0.628)\approx0.3266[/tex]

where [tex]F_Z(z)[/tex] is the cumulative distribution function for the random variable [tex]Z[/tex] following the standard normal distribution.

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