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14-02-2017
Mathematics

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H=K+log(A/C)
isolate a... make a the subject

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arthurpdc arthurpdc

14-02-2017

[tex]H=K+\log\left(\dfrac{A}{C}\right)\\\\ \log\left(\dfrac{A}{C}\right)=H-K\\\\ \dfrac{A}{C}=10^{H-K}\\\\ \boxed{A=C\cdot10^{H-K}}[/tex]

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