Answer:
Option A [tex]41.9\ ft^{3}[/tex]
Step-by-step explanation:
we know that
The volume of a cone is equal to
[tex]V=\frac{1}{3}\pi r^{2} h[/tex]
In this problem we have
[tex]r=4/2=2\ ft, h=10\ ft[/tex]
substitute the values
[tex]V=\frac{1}{3}\pi (2)^{2}(10)[/tex]
[tex]V=41.9\ ft^{3}[/tex]
