pitbull12907
pitbull12907
11-10-2022
Mathematics
contestada
please please help me out
Respuesta :
GracieKate5976
GracieKate5976
11-10-2022
.
[tex]Pr(x)=\sum_{x\mathop{=}0}^nnC_x\times p^x\times q^{n-x}[/tex][tex]x=0,\text{ n=43, p=}\frac{1}{124},\text{ q=1-}\frac{1}{124}=\frac{123}{124}[/tex]
[tex]Pr(x=0)=43C_0\frac{}{}\times(\frac{1}{124})^0\times(\frac{123}{124})^{43}=0.71[/tex]
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