Given data
*The given length of the cable is L = 15.4 m
*The given angle is
[tex]\theta=33.5^0[/tex]
The formula for the height is given as
[tex]h=L(1-\cos \theta)[/tex]
Substitute the values in the above expression as
[tex]\begin{gathered} h=15.4(1-\cos 33.5^0) \\ =2.57\text{ m} \end{gathered}[/tex]
The formula for the velocity of the ball at the bottom of its swing is given as
[tex]v=\sqrt[]{2gh}[/tex]
[tex]\begin{gathered} v=\sqrt[]{2\times9.8\times2.57} \\ =7.09\text{ m/s} \end{gathered}[/tex]
