quanntwann13148 quanntwann13148
  • 11-10-2022
  • Mathematics
contestada

hello, the question is in the picture :)

hello the question is in the picture class=

Respuesta :

kylaprimus9567 kylaprimus9567
  • 11-10-2022

By cross multiplying the given equation, we have

[tex]6x=(x-2)(x+8)[/tex]

By multiplying the right hand side, we get

[tex]6x=x^2+6x-16[/tex]

Then, by subtracting 6x to both sides, we have

[tex]0=x^2-16[/tex]

or equivalently,

[tex]x^2-16=0[/tex]

Since the left hand side is a conjugate binomial, it can be expressed as

[tex]x^2-16=(x+4)(x-4)[/tex]

Then, we have the equation

[tex](x+4)(x-4)=0[/tex]

Therefore, the values of x that make the equation true are x= 4 and x= -4

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