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dexteright02
Data:
Molar Mass of (C6H12O6)
C = 6*12 = 72 amu
H = 12*1 = 12 amu
O = 6*16 = 96 amu
----------------------------
Molar Mass of (C6H12O6) = 72 + 12 + 96 = 180 g/mol

If:

180 g → 1 mol
y → 3.25 mols

Solving: Rule of three (directly proportional)

[tex] \frac{180}{y} = \frac{1}{3.25} [/tex]
multiply cross
[tex]1*y = 180*3.25[/tex]
[tex]\boxed{\boxed{y = 585\:grams\:of\:glucose}}\end{array}}\qquad\quad\checkmark[/tex]

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