jillbeanburke
jillbeanburke
17-02-2017
Mathematics
contestada
sin^2xcos^2x=1-cos4x/8
Respuesta :
LammettHash
LammettHash
17-02-2017
[tex]\sin^2x\cos^2x=\left(\dfrac{1-\cos2x}2\right)\left(\dfrac{1+\cos2x}2\right)=\dfrac{1-\cos^22x}4=\dfrac{1-\dfrac{1+\cos4x}2}4=\dfrac{2-(1+\cos4x)}8=\dfrac{1-\cos4x}8[/tex]
Answer Link
VER TODAS LAS RESPUESTAS ( 93+ )
Otras preguntas
Sara has had mouth cancer,an early onset of menopause,and issues with cholesterol. Which drug does sara mostly likely abuse?
correct the dialogue.are you afraid of snakes asked henry
What's the perimeter for this
Letters a, b, c, and d are angles measures. Which equation is enough information to prove that lines m and n are parallel lines cut by transversal p? Check all
Given that 1 meter = 1 x 109 nanometers, what is the diameter of the average cell in the human body, in nanometers? The diameter of the average cell in the huma
Fill in the blanks with the correct forms of the present tense of the verbs given in the brackets| 1) she ..... in her room at the moment.(play) 2) the teacher
Shrek the musical type of performance presentational or representational
What is the smallest defined unit of time on the geological scale?
Easy question: What continent is Finland in?
what is human relation