15-12-2022
Mathematics

contestada

How would i solve for E

How would i solve for E class=

Respuesta :

Medunno13 Medunno13

15-12-2022

Answer:

5/13

Step-by-step explanation:

[tex]CE=\sqrt{10^2 + 24^2}=26 \\ \\ \cos E=\frac{10}{26}=\frac{5}{13}[/tex]

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