shanepierce shanepierce
  • 13-03-2017
  • Mathematics
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Algebra II Help??? Subtracting Fractions

(2x)/(y^2-x^2) - (x)/(y-x)

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apologiabiology
apologiabiology apologiabiology
  • 13-03-2017
make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
[tex] \frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2} [/tex]=
[tex]\frac{2x-x(x+y)}{y^2-x^2}[/tex]=
[tex]\frac{2x-x^2-xy}{y^2-x^2}[/tex]
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