Seudónimo Seudónimo
  • 14-03-2017
  • Physics
contestada

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

Respuesta :

Аноним Аноним
  • 14-03-2017
vf^2 = vi^2 + 2*a*d
---
vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters
Answer Link

Otras preguntas

What is the median number for the numbers 4, 8, 10, 5, 9
The difference of 9 and the quotient of a number t and 6 is 5
Which South African city is a regional hub of commerce and has South Africa's premier international airport? a. Johannesburg b. Cape Town c. Durban d. Pret
What is the 7th term of the sequence 3,12,48,192
170 is 1/10 of 17 true or false
which modern european country occupies the homeland of the ancient romans
How many molecules (not moles) of NH3 are produced from 5.01×10−4 g of H2?
the US government gave land to the railroads to help them expand what impact did these land grants have our industries in the West
Which of the following factors MOST likely led to the development of the longhouse -- a narrow, bark-covered, and long dwelling used as a shelter by the Iroquoi
What is 3/10 in simplest form