dancatalin811 dancatalin811

15-03-2017
Mathematics

contestada

Suma a trei numere este 130. Stiind ca ele sunt invers proportionale cu numerele 2,3,4 aflati numerele

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smpurvis smpurvis

15-03-2017

A+b+c=130 a,b,c ip cu 2,3,4 2a=3b=4c=k a=k/2 b=k/3 c=k/4 k/2 + k/3+ k/4= 130 aducem la acelasi numitor (12) 6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30

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Аноним Аноним

15-03-2017

6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30, hope that helps!!

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