SanithN0ewyo SanithN0ewyo
  • 11-04-2017
  • Physics
contestada

If the length of the centrifuge arm is 12.0 m , at what speed is the rider moving when she experiences 10 g's?

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sharmaenderp
sharmaenderp sharmaenderp
  • 13-04-2017
The rider experienced a centripetal acceleration of 10 g's. Given that we have gravity approximated as 9.8 m/s², then 10G = 10(9.8) = 98 m/s². 

Recall that centripetal acceleration can be expressed in terms of distance and v. We have

[tex] a_{centripetal} = \frac{v^{2}}{r} [/tex]

or re-arranging the equation, 
[tex]v = \sqrt{(a_{centripetal})(r)} \\ v = \sqrt{98(12)}\\ v = 34.3 m/s [/tex].

Answer: 34.3 m/s

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