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konrad509
[tex]n+n+1+n+2=180\\ 3n+3=180\\ 3n=177\\ n=59\\ n+1=60\\ n+2=61[/tex]

Those numbers are 59,60,61.
AL2006

If the integers were all the same, then each one would be 1/3 of 180 = 60.

-- Put all three 60s on the table in front of you. 

-- Take ' 1 ' away from the first one and drop it on the last one. 

-- Then you have  59,  60, and  61, and their sum is still  180.


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