sydneysnyder0202
sydneysnyder0202
12-05-2017
Mathematics
contestada
Solve S = 2ab + 2bc + 2ac for b
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Dylanblox7
Dylanblox7
12-05-2017
A = 2ab + 2ac + 2bc
A = 2b(a + c) + 2ac
2b(a + c) = A - 2ac
b = (A - 2ac) / [2(a + c)]
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BHmohammad
BHmohammad
12-05-2017
take b as a common factor
s=b (2a + 2c) +2 ac
s-2ac=b (2a+2c)
b=(s-2ac)/(2a+2c)
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