kmvqbzrm kmvqbzrm
  • 15-05-2017
  • Mathematics
contestada

2log(x-3)+1=5

can someone explain how to solve for x?

Respuesta :

jdoe0001 jdoe0001
  • 15-05-2017
[tex]\bf 2log(x-3)+1=5\iff 2log_{10}(x-3)+1=5\\\\\\ 2log_{10}(x-3)=4 \\\\\\ log_{10}(x-3)=\cfrac{4}{2}\implies log_{10}(x-3)=2\\\\ -----------------------------\\\\ {{ a}}^{log_{{ a}}x}=x\impliedby \textit{using this cancellation rule}\\\\ -----------------------------\\\\ 10^{\cfrac{}{}log_{10}(x-3)}=10^2\implies x-3=10^2\implies x=100+3[/tex]
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