Respuesta :

AyaZ
[tex] (\frac{1}{5} ( x^{2} -2x) = \frac{-2}{5} + x^{2} )*5 \\ \\ x^{2} -2x=-2+5 x^{2} \\ 4 x^{2} +2x-2=0 \\ Because \\ a x^{2} +bx+c=0 \\ a+c=b \\ x_{1} =-1 \\ x_{2} = \frac{-c}{a} = \frac{-(-2)}{4} = \frac{1}{2} [/tex]