Respuesta :

konrad509
[tex]-7\leq4x+1\leq5\\ -8\leq4x \leq4\\ -2\leq x\leq1 \Longleftrightarrow x\geq-2 \wedge x\leq1 \Rightarrow C [/tex]
[tex]-7\leq4x+1\leq5\ \ \ \ |subtract\ 1\\\\-7-1\leq4x+1-1\leq5-1\\\\-8\leq4x\leq4\ \ \ \ |divide\ by\ 4\\\\-8:4\leq4x:4\leq4:4\\\\\boxed{-2\leq x \leq1\Rightarrow x\in[-2;\ 1]}[/tex]

[tex]\boxed{x\geq-2\ and\ x\leq1}\to\answer{\boxed{C}}[/tex]