3CuCl2(aq) + 2Al(s) mc001-1.jpg 3Cu(s) + 2AlCl3(aq) If 10.5 g copper chloride react with 12.4 g aluminum, what is the limiting reactant?

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12-06-2017
Chemistry

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3CuCl2(aq) + 2Al(s) mc001-1.jpg 3Cu(s) + 2AlCl3(aq) If 10.5 g copper chloride react with 12.4 g aluminum, what is the limiting reactant?

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dec77cat dec77cat · Answer 1 · 2017-06-12T14:53:31+02:00

dec77cat dec77cat

12-06-2017

3CuCl₂ + 2Al = 3Cu + 2AlCl₃

m(CuCl₂)=10.5 g
M(CuCl₂)=134.45 g/mol
n(CuCl₂)=10.5/134.45=0.0781 mol

m(Al)=12.4 g
M(Al)=26.98 g/mol
n(Al)=12.4/26.98=0.4596

CuCl₂:Al = 3:2
0.0781:0.4596 ⇒ 3:17.7

the limiting reactant is CuCl₂

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k0kichi0ma k0kichi0ma · Answer 2 · 2020-11-20T18:31:29+01:00

k0kichi0ma k0kichi0ma

20-11-2020

Answer:

CuCI2 is the limiting reactant.

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