Respuesta :

LeChatNoir
mFe: 56 g/mol
mFe₂O₃: 160 g/mol
------------------------------
2Fe₂O₃----> 4Fe + 3O₂ 
160g·2         56g·4    
 

320g Fe₂O₃  --------- 224g Fe
375g Fe₂O₃  --------- X
X = (224×375)/320
X = 262,5g Fe

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