youngmoney206orwy3j youngmoney206orwy3j

13-07-2017
Physics

contestada

A 60 W lightbulb is on for 24 hours. A stereo with a power of 150 W is on for 2 hours. Which statement correctly compares the energy used by these devices?

Respuesta :

sophiemcdo sophiemcdo

16-07-2017

P=∆E/∆t. ∆E=P×∆t
Lightbulb: ∆E=60×(24×3600) the unit of the time has to be seconds
Stereo: ∆E= 50×(2×3600)

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khunter81 khunter81

24-06-2020

Answer:

The lightbulb uses 4,104,000 J more than the stereo.

Explanation:

Answer Link

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