First find the hypotenuse of the right triangle bases.
a^2 + b^2 = c^2
4^2 + 6^2 = c^2
16 + 36 = c^2
52 = c^2
2√13 = c
Triangle bases:
A = (1/2) * b * h * 2
A = (1/2) * 4 * 6 * 2
A = 24 ft^2
Front Rectangle: Left side Rectangle Back Side Rectangle
A = 8 * 2√13 = 16√13 ft^2 A = 4 * 4 = 32 ft^2 A = 6 * 8 = 48 ft^2
24 + 32 + 48 + 16√13 = Total area = 104 + 16√13 ft^2
