first, find where they are equal because g(x) grows at a faster rate so it will somwehre start to go past f(x)
solve for x such that f(x)=g(x) so 3x+30=x²+20 minus (3x+30) both sides 0=x²-3x-10 facotr what 2 numbers multiply to get -10 and add to get -3? -5 and 2 0=(x-5)(x+2)
set each to zero
0=x-5 5=x
0=x+2 -2=x
at x=5 and -2
test points between them at x=-3, g(x)>f(x) at x=0, f(x)>g(x) at x=6, g(x)>f(x)
so g(x)>f(x) when x<-2 or x>5
so I think the teacher is looking for that point when g(x)<f(x) then g(x)>f(x) so that would be at x=5
