The given quadratic function is in vertex form, y = a(x - h)^2 + k, where (h, k) represents the vertex.
For the function y = -2(x - 1)^2 - 2:
- The vertex is (h, k) = (1, -2).
- The coefficient "a" is -2, indicating a downward-opening parabola.
So, the vertex of the parabola y = -2(x - 1)^2 - 2 is (1, -2), and it opens downward.
