Answer:
5[tex]w^{22}[/tex]
Step-by-step explanation:
using the properties of exponents
• [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]
• [tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex]
given
[tex]\frac{-20w^{7} }{-4(w^-5)^3}[/tex]
= [tex]\frac{-20}{-4}[/tex] × [tex]\frac{w^7}{w^-15}[/tex]
= 5 × [tex]w^{7-(-15)}[/tex]
= 5 [tex]w^{(7+15)}[/tex]
= 5[tex]w^{22}[/tex]
