If 824 grams of NH3 and excess oxygen gas react to produce nitrogen oxide and water, how many moles of nitrogen oxide are formed?
2_ NH3 + 3 O2 3 H₂O + 2 N2O3

Question

14-01-2024
Chemistry

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If 824 grams of NH3 and excess oxygen gas react to produce nitrogen oxide and water, how many moles of nitrogen oxide are formed?
2_ NH3 + 3 O2 3 H₂O + 2 N2O3

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sushrutsarode28710 sushrutsarode28710 · Answer 1 · 2024-01-14T09:53:06+01:00

Answer:

The moles of N2O3 will be the same as the moles of NH3

Explanation:

The molar mass of NH3 (ammonia) is approximately 17 grams/mol. So, for 824 grams of NH3:

824g/(17g/mol)

Now, calculate that to find the moles of NH3.

Next, we look at the balanced chemical equation. According to the equation, 2 moles of NH3 react to produce 2 moles of N2O3.

2NH3+3O2→3H2O+2N2O3

So, if we know the moles of NH3, we can directly find the moles of N2O3. Since the ratio is 1:1, the moles of N2O3 will be the same as the moles of NH3.

If 824 grams of NH3 and excess oxygen gas react to produce nitrogen oxide and water, how many moles of nitrogen oxide are formed? 2_ NH3 + 3 O2 3 H₂O + 2 N2O3

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Otras preguntas

If 824 grams of NH3 and excess oxygen gas react to produce nitrogen oxide and water, how many moles of nitrogen oxide are formed?
2_ NH3 + 3 O2 3 H₂O + 2 N2O3