log3 5x = log5 (2x + 8) implies log3 5x =
2log5 . x + 8log5
log3 5x - 2log5 . x = 8log5 and (5log3 -
2log5)x = 8log5
Finally, x = 8log5 / (5log3 - 2log5) = a
let y = log5 (2x + 8), so y(a) = log5 (2a + 8)
The point approximating the solution is P( a, y(a))
or
P ( 8log5 / (5log3 - 2log5, log5[2 (8log5 / (5log3 - 2log5)) + 8])
Therefore,
by graphing a system of equations, the points that approximate the solution for
Tenisha’s system of equations are points (1.0, 1.4).
