take derivitive
y'=-2x+3
at x=2
y'=-2(2)+3
y'=-4+3
y'=-1
slope is -1
find the value of y when x=2
y=-(2)^2+3(2)+8
y=-4+6+8
y=10
(2,10) and slope is -1
use point slope form
y-y1=m(x-x1)
a point is (x1,y1) and the slope is m
so
y-10=-1(x-2)
y-10=-x+2
y=-x+12
2nd option
