bhjznensb
bhjznensb
14-08-2017
Mathematics
contestada
Eliminate the parameter. X=sqrt of t y = 2t+5
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Аноним
Аноним
14-08-2017
x = sqrt
t = x^2
y = 2t + 5
2t = y - 5
t = (y - 5)/2
so x^2 = (y - 5) / 2
2x^2 = y - 5
y = 2x^2 + 5
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