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  • 14-09-2017
  • Mathematics
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4 times the lesser of two consecutive even integers is 12 less than twice the greater number. find the integers

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Аноним Аноним
  • 21-09-2017
Let the two consecutive even integers be 2n + 2n + 2.

4 times the lesser of the two integers is 12 less than twice the greater number. Therefore
4(2n) = 2(2n + 2) - 12
8n = 4n + 4 - 12
4n = -8
n = -2

Therefore
2n = -4
2n + 2 = -2

Answer:
The integers are -4 and -2.
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